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04-03-2018
Mathematics

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The function f is defined by f(x) x2 +3x-10.

If fx +5)x2 +kx+30, k = [?]

Find the smallest zero of f(x+5). x = [?]

The function f is defined by fx x2 3x10 If fx 5x2 kx30 k Find the smallest zero of fx5 x class=

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tynollette tynollette

04-03-2018

f(x+5)=(x+5)²+3(x+5)-10
f(x)=x²+10x+25+3x+15-10
f(x)=x²+13x+30
k=13

x²+13x+30=0
(x+3)(x+10)=0
x=-3 or -10
the smallest zeros is x=-10

Answer Link

clouds122 clouds122

15-04-2021

Answer:

K=13

X=-10

Step-by-step explanation:

Answer Link

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