Respuesta :
Follow a simple procedure, if [tex]y=x^n[/tex] then [tex] \frac{dy}{dx} = nx^{n-1} [/tex] so,
[tex]y=4x^3+3x^2+2 \Rightarrow \frac{dy}{dx} = 12x^2+6x [/tex]
(bearing in mind constant terms disappear when differentiated)
[tex]y=4x^3+3x^2+2 \Rightarrow \frac{dy}{dx} = 12x^2+6x [/tex]
(bearing in mind constant terms disappear when differentiated)
Answer:
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Step-by-step explanation:
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