Respuesta :

[tex]\sin (A)=\frac{CO}{H}[/tex]

Where CO = Opposite catete = 3

H = Hypotenuse = 10

[tex]\sin (A)=\frac{3}{10}=0.3[/tex][tex]\begin{gathered} \sin ^{-1}(0.30)=A \\ \end{gathered}[/tex][tex]A=17.46\degree[/tex]

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