ariannasmith006 ariannasmith006

05-04-2022
Mathematics

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What are the solution(s) for the quadratic equation?

Y=x^2-2x+1

Respuesta :

Аноним Аноним

05-04-2022

[tex]\\ \rm\rightarrowtail x^2-2x+1=0[/tex]

[tex]\\ \rm\rightarrowtail x^2-x-x+1=0[/tex]

[tex]\\ \rm\rightarrowtail x(x-1)-1(x-1)=0[/tex]

[tex]\\ \rm\rightarrowtail (x-1)(x-1)=0[/tex]

[tex]\\ \rm\rightarrowtail x=1[/tex]

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