Answer:
Step-by-step explanation:
From the given trapezium, the following can be observed:
i. trapezium ABCD
ii. AB || DC
iii. EF || AB
iv. EF || DC
Let AD ≅ BC, then:
AD = AE + ED
BC = BF + FC
So that with the condition that;
AE ≅ BF
and
ED ≅ CF
So then;
AE:ED ≅ BF:FC
Which implies that;
[tex]\frac{AE}{ED}[/tex] = [tex]\frac{BF}{FC}[/tex]
