Answer:
Well
STP
specifies 100⋅kPa,and 273.15⋅K...
Explanation:
And so we solve for n
moles of gas
in the Ideal Gas equation, and of course we have to fish out an appropriate gas constant...
n=PVRT=100⋅kPa×10⋅L8.314⋅L⋅kPa⋅K−1⋅mol−1×273.15⋅K
=0.440⋅mol
And thus a mass of 0.440⋅mol×20.18⋅g⋅mol−1...approx. 9⋅g...
Explanation:
