Respuesta :

mn33012342

Answer:

For y=Ax? +BX+ +C, a. find y' f'(x) = 3* Ax2+2*Bx+0 f(x) = 3 Ax2+2Bx b. find the value(s) of x so that y'=l. f(0) = 3A(0)2+2B(0) f(0) = 0 c. find y" f''(x) = 2*3Ax+3B(1) f'(x) = 6Ax+3B

Step-by-step explanation: