Answer:
[tex]\rho =10.07\frac{lb}{cup}[/tex]
Explanation:
Hello,
In this case, given that 1 cup equals 236.588 mL and 1 pound equals 453.6 g, the required density in pounds per cup turns out:
[tex]\rho =19.3\frac{19.3g}{mL}*\frac{1lb}{453.6g}*\frac{236.588mL}{1cup}\\ \\\rho =10.07\frac{lb}{cup}[/tex]
Best regards.
