Answer:
C
Step-by-step explanation:
Δ AQP and Δ ACB are similar triangles, thus the ratios of corresponding sides are equal, that is
[tex]\frac{AQ}{AC}[/tex] = [tex]\frac{PQ}{BC}[/tex] ( note that AC = 3 + 6 = 9 ), substitute values
[tex]\frac{3}{9}[/tex] = [tex]\frac{4.5}{BC}[/tex] ( cross- multiply )
3BC = 40.5 ( divide both sides by 3 )
BC = 13,5 cm → C
