Answer:
Step-by-step explanation:
hello
[tex]y^2-4y+6= (y+1)^2-2y-1-4y+6=(y+1)^2-6y+5=(y+1)^2-6(y+1)+11[/tex]
so
[tex]\dfrac{y^2-4y+6}{y+1}=y+1-6+\dfrac{11}{y+1}=y-5+\dfrac{11}{y+1}[/tex]
hope this helps
