Answer:
[tex]\frac{3xy}{2}[/tex]
Step-by-step explanation:
Given
[tex]\frac{5y^2}{3}[/tex] × [tex]\frac{9x}{10y}[/tex]
Cancel 5y² and 10y by 5y and cancel 3 and 9x by 3, leaving
= [tex]\frac{y}{1}[/tex] × [tex]\frac{3x}{2}[/tex]
= [tex]\frac{3xy}{2}[/tex]
