Respuesta :

mshahzaib247

Answer:

v = 22492 ms^-1

Explanation:

[tex]1/2 m v^2 = kqQ / r[/tex]

[tex]v = \sqrt{2kqQ / rm}[/tex]

[tex]v = \sqrt{2*(9*10^9)*(1.6*10^-19)*(1.6 * 10^-15) / (0.01)*(9.109*10^-31)}[/tex]

v = 22492 ms^-1

v = 22.492 k ms^-1