Answer: 225.75g
Explanation:
Molar Mass of Fe(OH)2 = 56 + 2(16 + 1) = 56 + 2(17) = 56 + 34 = 90g/mol
1mole(90g) of Fe(OH)2 contained 6.02x10^23 units.
Therefore, Xg of Fe(OH)2 will contain 1.51x10^24 units
Xg of Fe(OH)2 = (90x1.51x10^24)/6.02x10^23 = 225.75g
