Answer:
[tex]\large\boxed{\sqrt{130}\approx11}[/tex]
Step-by-step explanation:
[tex]\sqrt{a}=b\iff b^2=a\\\\11<\sqrt{130}<12\\\\\text{because}\ 11^2=121<130\ \text{and}\ 12^2=144>130\to121<130<144.\\\\\text{We calculate the difference to check closer to which number a given root is}\\\\130-121=9\\144-130=14\\\\\text{closer to 11}[/tex]
