Answer:
3b² -6b -48
Step-by-step explanation:
Given : 3b(b-4) and 6(b-8).
To find : What is the sum.
Solution : We have given 3b(b-4) and 6(b-8).
According to question :
3b(b-4) + 6(b-8).
Distribute 3b over b-4 and 6 over b-8.
3b² -12b + 6b -48.
Combine like terms.
3b² -6b -48.
Therefore,3b² -6b -48.
