we are given
logb (2)= 2.212
logb(3)=3.415
we can use log formula
[tex] log(24)=log(8*3) [/tex]
[tex] log(24)=log(8)+log(3) [/tex]
[tex] log(24)=log(2^3)+log(3) [/tex]
[tex] log(24)=3log(2)+log(3) [/tex]
now, we can plug values
[tex] log(24)=3*2.212+3.415 [/tex]
[tex] log(24)=10.051 [/tex]................Answer
